1840 United States presidential election in Indiana

1840 United States presidential election in Indiana
November 2, 1840
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 9 0
Popular vote 65,302 51,604
Percentage 55.86% 44.14%
County Results
President before election

Martin Van Buren
Democratic

 Elected President

William Henry Harrison
Whig

A presidential election was held in Indiana on November 2, 1840 as part of the 1840 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Indiana by a margin of 11.72%.

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