1840 United States presidential election in Ohio

1840 United States presidential election in Ohio
	October 30, 1840
Harrison 40–50% 50–60% 60–70% 70–80%	Van Buren 50–60% 60–70% 70–80%
President before election; Martin Van Buren; Democratic	Elected President ; William Henry Harrison; Whig

A presidential election was held in Ohio on October 30, 1840 as part of the 1840 United States presidential election. Voters chose 21 representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Ohio by a margin of 8.53%. Ohio was the home state of William Henry Harrison, Harrison improved his margin of victory from the last election over Van Buren by +4.22%