1844 United States presidential election in Rhode Island
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County Results
Clay 50–60% 60–70% 70–80% 80–90%
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| Elections in Rhode Island |
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A presidential election was held in Rhode Island on November 6, 1844 as part of the 1844 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Rhode Island voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won Rhode Island by a margin of 19.97%.
With 59.55% of the popular vote, Rhode Island would prove to be Henry Clay's strongest state in the nation.