1988 United States Senate elections
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33 of the 100 seats in the United States Senate 51 seats needed for a majority | ||||||||||||||||||||||||||||||||||||||||
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Results of the elections: Democratic gain Democratic hold Republican gain Republican hold No election | ||||||||||||||||||||||||||||||||||||||||
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The 1988 United States Senate elections were elections for the United States Senate. Held on November 8, 1988, the 33 seats of Class 1 were contested in regular elections. In spite of the Republican victory by George H. W. Bush in the presidential election, the Democrats gained a net of one seat in the Senate. Seven seats changed parties, with four incumbents being defeated. The Democratic majority in the Senate increased by one to 55–45.
This is the last Senate election cycle in which California voted for a Republican, the last in which Texas and Maine voted for a Democrat, and the last time Arizona voted for a Democrat until 2018. This would also be the last Senate election cycle until 1998 to not have at least one special election during that cycle.
This is also the last Senate election cycle in which no woman was elected to the Senate from either party, as all of the winners were men.