1992 United States presidential election in Minnesota|
|
| Turnout | 73.91% |
|---|
|
|
|
Clinton
20–30%
30–40%
40–50%
50–60%
60–70%
70–80%
80–90%
90–100% |
Bush
20–30%
30–40%
40–50%
50–60%
60–70%
70–80%
80–90%
90–100% |
Perot
30–40%
40–50%
50–60%
60–70%
70–80%
90–100% |
Other
30–40% |
Tie/no data
|
|
|
The 1992 United States presidential election in Minnesota took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.
Minnesota was won by Governor Bill Clinton (D-Arkansas) with 43.48% of the popular vote over incumbent President George H. W. Bush (R-Texas) who took 31.85%, a victory margin of 11.63%. Businessman Ross Perot (I-Texas) finished third, with 23.96% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.
April 7, 1992 saw the first presidential primary in Minnesota since 1956. Clinton won a plurality of votes in the DFL primary, and Bush won in the IR election.
Clinton became the first Democrat to win the White House without carrying Lyon or Roseau counties since Woodrow Wilson in 1912, as well as the first to do so without carrying Becker County since Woodrow Wilson in 1916.
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