1992 United States presidential election in Wisconsin|
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Clinton
30–40%
40–50%
50–60%
60–70%
70–80%
80–90%
90–100% |
Bush
30–40%
40–50%
50–60%
60–70%
70–80%
80–90%
90–100% |
Perot
30–40%
40–50%
50–60% |
Tie/No Data
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The 1992 United States presidential election in Wisconsin took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose 11 representatives, or electors, to the Electoral College, who voted for president and vice president.
Wisconsin was won by Governor Bill Clinton (D-Arkansas) with 41.13 percent of the popular vote over incumbent President George H. W. Bush (R-Texas) with 36.78 percent. Businessman Ross Perot (I-Texas) finished third, with 21.51 percent of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.
As of the 2024 presidential election, this is the last election in which Florence County voted for a Democratic presidential candidate, and the last time that Door County backed a losing candidate until 2024. Despite Clinton's decently solid victory in Wisconsin, it marks his narrowest one in a state that Michael Dukakis won in 1988.
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