1996 United States presidential election in Missouri|
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Congressional district results
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Clinton
40–50%
50–60%
60–70%
70–80% |
Dole
40–50%
50–60%
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The 1996 United States presidential election in Missouri took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose eleven representatives, or electors to the Electoral College, who voted for president and vice president.
Missouri was won by incumbent President Bill Clinton (D-AR) over Senator Bob Dole (R-KS), with Clinton winning 47.54% to Dole's 41.24% for a winning margin of 6.3%. Billionaire businessman Ross Perot (Reform-TX) finished in third, with 10.06% of the popular vote. From 1904 to 2004, the state was carried by the winner of the presidential election each time with the exception of 1956. The state was carried by the Republicans in 2000, and continued to move rightward in future elections with its white, rural, culturally conservative population following in the direction of neighboring Southern states like Arkansas. Missouri lost its bellwether status after voting significantly more Republican than the nation since 2008. The state did nearly vote for Barack Obama in 2008.
1996 marked the most recent time in which Missouri has voted Democratic, as well as the last time that Hickory, Benton, Mercer, Caldwell, Grundy, Crawford, Carroll, Franklin, St. Clair, Livingston, DeKalb, Lafayette, St. Francois, Daviess, Bates, Madison, Montgomery, Sullivan, Clark, Nodaway, Henry, Vernon, Gentry, Macon, Knox, Wayne, Ripley, Clinton, Monroe, Ralls, Randolph, Dunklin, Reynolds, Oregon, Howard, Shannon, Shelby, Callaway, Scott, Lincoln, Audrain, Pike, Marion, Lewis, Scotland, Schuyler, Chariton, Worth, and Linn Counties voted for a Democratic presidential candidate.