2008 Australian Open – Women's singles

Women's singles
2008 Australian Open
Champion Maria Sharapova
Runner-up Ana Ivanovic
Score7–5, 6–3
Draw128 (12 Q / 8 WC)
Seeds32

Maria Sharapova defeated Ana Ivanovic in the final, 7–5, 6–3 to win the women's singles tennis title at the 2008 Australian Open. It was her third major singles title, and she became the first Russian to win the title. Sharapova did not lose a set during the tournament, or face a tiebreak in any set. It was Ivanovic's second runner-up finish in as many major finals, though she would win the French Open a few months later.

Serena Williams was the defending champion, but was defeated in the quarterfinals by Jelena Janković.

Justine Henin's winning streak of 33 matches (beginning at the 2007 Rogers Cup) ended with her defeat in the quarterfinals to Sharapova.

Agnieszka Radwańska became the first Pole to reach a major quarterfinal in the Open Era, and the first to do so since Jadwiga Jędrzejowska in the 1939 Wimbledon Championships.

This was the first Australian Open appearance for future champion Caroline Wozniacki, who lost to Ivanovic in the fourth round.