Alexandrovsk-Sakhalinsky District

Alexandrovsk-Sakhalinsky District
Александровск-Сахалинский район
Coastal landscape, Alexandrovsk-Sakhalinsky District
Location of Alexandrovsk-Sakhalinsky District in Sakhalin Oblast
Coordinates: 50°54′N 142°09′E / 50.900°N 142.150°E / 50.900; 142.150
CountryRussia
Federal subjectSakhalin Oblast
Administrative centerAlexandrovsk-Sakhalinsky
Area
  Total
4,777.4 km2 (1,844.6 sq mi)
Population
  Total
2,791
  Density0.58/km2 (1.5/sq mi)
  Urban
0%
  Rural
100%
Administrative structure
  Inhabited localities1 cities/towns, 13 rural localities
Municipal structure
  Municipally incorporated asAlexandrovsk-Sakhalinsky Urban Okrug
Time zoneUTC+11 (MSK+8 )
OKTMO ID64704000
Websitehttp://www.aleks-sakh.ru/

Alexandrovsk-Sakhalinsky District (Russian: Алекса́ндровск-Сахали́нский райо́н) is an administrative district (raion) of Sakhalin Oblast, Russia, one of the seventeen in the oblast. As a municipal division, it is incorporated as Alexandrovsk-Sakhalinsky Urban Okrug. It is located in the west of the oblast. The area of the district is 4,777.4 square kilometers (1,844.6 sq mi). Its administrative center is the town of Alexandrovsk-Sakhalinsky. Population (excluding the administrative center): 2,791(2010 Census); 4,687(2002 Census); 8,526(1989 Soviet census).

Historical population
YearPop.±%
195942,593    
197035,862−15.8%
197929,256−18.4%
198927,810−4.9%
200217,513−37.0%
201013,404−23.5%
202110,221−23.7%
Source: Census data