Selinsgrove, Pennsylvania

Selinsgrove, Pennsylvania
Selinsgrove, Pennsylvania
Nickname: 
The Grove
Location of Selinsgrove in Snyder County, Pennsylvania.
Selinsgrove
Location within the U.S. state of Pennsylvania
Selinsgrove
Selinsgrove (the United States)
Coordinates: 40°48′09″N 76°51′47″W / 40.80250°N 76.86306°W / 40.80250; -76.86306
CountryUnited States
StatePennsylvania
CountySnyder
Government
  MayorJeff Reed
Area
  Total
1.90 sq mi (4.92 km2)
  Land1.83 sq mi (4.74 km2)
  Water0.07 sq mi (0.18 km2)  3.7%
Elevation
(borough benchmark)
444 ft (135 m)
Highest elevation
(southwest boundary of borough)
600 ft (182 m)
Lowest elevation
(Susquehanna River)
418 ft (127 m)
Population
 (2020)>
  Total
5,761
  Estimate 
(2021)
5,741
  Density3,223.38/sq mi (1,244.33/km2)
Time zoneUTC-5 (Eastern (EST))
  Summer (DST)EDT
ZIP code
17870
Area code(s)570 and 272
FIPS code42-69216
WebsiteBorough Website

Selinsgrove /ˈs.lɪnzˌɡrv/ is the largest borough in Snyder County, Pennsylvania, United States. The population is estimated to be 5,761 for the 2020 Census.

Selinsgrove is geographically located in the middle of the Susquehanna River Valley in Central Pennsylvania, along U.S. Routes 11 and 15, 45 miles north of Harrisburg and 5.7 miles (9.2 km) southwest of Sunbury. It is the home of Susquehanna University.