1840 United States presidential election in Alabama

1840 United States presidential election in Alabama
November 9, 1840
 
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard M. Johnson John Tyler
Electoral vote 7 0
Popular vote 33,996 28,518
Percentage 54.38% 45.62%
President before election

Martin Van Buren
Democratic

 Elected President

William Henry Harrison
Whig

A presidential election was held in Alabama on November 9, 1840 as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Alabama voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Alabama by a margin of 8.76%. As of 2024, this remains the only time in American history that Alabama has voted for a different presidential candidate than neighboring Mississippi.

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