1840 United States presidential election in Maryland

1840 United States presidential election in Maryland
November 9, 1840
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 10 0
Popular vote 33,528 28,752
Percentage 53.83% 46.17%
County Results
President before election

Martin Van Buren
Democratic

 Elected President

William Henry Harrison
Whig

A presidential election was held in Maryland on November 9, 1840 as part of the 1840 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.

Maryland voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren, by a margin of 7.66%. As of 2020, this remains the only time in history that an incumbent Democratic president who served a full term has failed to carry any of Maryland's electoral votes in a reelection bid.

This was the first presidential election that Carroll County was able to vote in.

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.