1840 United States presidential election in Vermont

1840 United States presidential election in Vermont
November 10, 1840
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 7 0
Popular vote 32,445 18,009
Percentage 63.90% 35.47%
County Results
Harrison
  50–60%
  60–70%
  70–80%

President before election

Martin Van Buren
Democratic

 Elected President

William Henry Harrison
Whig

A presidential election was held in Vermont on November 10, 1840 as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Vermont by a margin of 28.43%.

Harrison's 28.43% margin of victory made it his strongest victory in the election while he carried 63.90% of the popular vote made Vermont his second strongest state after Kentucky.

Harrison had previously won Vermont against Van Buren four years earlier.

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