1988 United States presidential election in Georgia

1988 United States presidential election in Georgia
	November 8, 1988
Turnout	61.53% (of registered voters) ; 47.41% (of voting age population)
Bush 40–50% 50–60% 60–70% 70–80%	Dukakis 40–50% 50–60% 60–70% 70–80%
President before election; Ronald Reagan; Republican	Elected President ; George H. W. Bush; Republican

The 1988 United States presidential election in Georgia took place on November 8, 1988. All 50 states and the District of Columbia were part of the 1988 United States presidential election. Georgia voters chose 12 electors to the Electoral College, which selected the president and vice president. Georgia was won by incumbent Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as vice president, and Dukakis ran with Texas Senator Lloyd Bentsen.

Only two counties failed to give one of the major party nominees an outright majority: Clarke, which gave Dukakis a narrow plurality, and Bibb, which gave Bush a narrow plurality. Bush won four counties that had voted for Walter Mondale in 1984, out of only seven such counties nationwide. Georgia was one of only two states that Bush carried in 1988 which had voted for Jimmy Carter in 1980, the other being Maryland.