1996 United States presidential election in Washington (state)

1996 United States presidential election in Washington (state)
November 5, 1996
Turnout74.52% 8.08%
 
Nominee Bill Clinton Bob Dole Ross Perot
Party Democratic Republican Reform
Home state Arkansas Kansas Texas
Running mate Al Gore Jack Kemp Pat Choate
Electoral vote 11 0 0
Popular vote 1,123,323 840,712 201,003
Percentage 49.84% 37.30% 8.92%
President before election

Bill Clinton
Democratic

 Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in Washington took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.

The State of Washington was won by President Bill Clinton (D–AR) over Senator Bob Dole (R–KS), with Clinton winning 49.84% to 37.30% for a margin of 12.54%. Billionaire businessman Ross Perot (Reform–TX) finished in third, with 8.92% of the popular vote. As of the 2024 presidential election, this is the last election in which Spokane County, Kittitas County, Pend Oreille County, Ferry County, and Asotin County voted for a Democratic presidential candidate.

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