1836 United States presidential election in Arkansas

1836 United States presidential election in Arkansas
November 7, 1836
 
Nominee Martin Van Buren Hugh L. White
Party Democratic Whig
Home state New York Tennessee
Running mate Richard M. Johnson John Tyler
Electoral vote 3 0
Popular vote 2,380 1,334
Percentage 64.08% 35.92%
County results
President before election

Andrew Jackson
Democratic

 Elected President

Martin Van Buren
Democratic

A presidential election was held in Arkansas on November 7, 1836 as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Arkansas, having been admitted to the Union as the 25th state on June 15, 1836, voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White during its first presidential election. Van Buren won Arkansas by a margin of 28.16%.

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