1992 United States presidential election in Arkansas

1992 United States presidential election in Arkansas

November 3, 1992
 
Nominee Bill Clinton George H. W. Bush Ross Perot
Party Democratic Republican Independent
Home state Arkansas Texas Texas
Running mate Al Gore Dan Quayle James Stockdale
Electoral vote 6 0 0
Popular vote 505,823 337,324 99,132
Percentage 53.21% 35.48% 10.43%


President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

The 1992 United States presidential election in Arkansas took place on November 3, 1992, as part of the 1992 United States presidential election. State voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

Arkansas was won by incumbent Governor Bill Clinton (D) with 53.21% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 35.48%. Businessman Ross Perot (I-Texas) finished in third, with 10.43% of the popular vote. Clinton thus won his home state by a wide margin of 17.73%, becoming the first Democratic candidate to win the state since Jimmy Carter in 1976. Arkansas and Washington, D.C., which Clinton also won, were the only contests in 1992 in which any candidate received an absolute majority of the popular vote.

50% of white voters supported Clinton, while 40% supported Bush.