1836 United States presidential election in Rhode Island

1836 United States presidential election in Rhode Island
November 23, 1836
 
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard M. Johnson Francis Granger
Electoral vote 4 0
Popular vote 2,964 2,710
Percentage 52.24% 47.76%
County Results
President before election

Andrew Jackson
Democratic

 Elected President

Martin Van Buren
Democratic

A presidential election was held in Rhode Island on November 23, 1836 as part of the 1836 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Rhode Island voted for Democratic candidate Martin Van Buren over Whig candidate William Henry Harrison. Van Buren won Rhode Island by a narrow margin of 4.48%.

This was the first time that Rhode Island ever voted for a Democratic presidential candidate, and Van Buren's performance would not be bettered by a Democrat in Rhode Island until Franklin D. Roosevelt in 1932.

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