1840 United States presidential election in Louisiana

1840 United States presidential election in Louisiana
November 3, 1840
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 5 0
Popular vote 11,296 7,616
Percentage 59.73% 40.27%
President before election

Martin Van Buren
Democratic

 Elected President

William Henry Harrison
Whig

A presidential election was held in Louisiana on November 3, 1840 as part of the 1840 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Louisiana voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Louisiana by a margin of 19.46%.

With 59.73% of the popular vote, Louisiana would prove to be Harrison's fourth strongest state after Kentucky, Vermont and Rhode Island.

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